5w^2+3w=92

Solution for 5w^2+3w=92 equation:

5w^2+3w=92

We move all terms to the left:

5w^2+3w-(92)=0

a = 5; b = 3; c = -92;
Δ = b2-4ac
Δ = 32-4·5·(-92)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-43}{2*5}=\frac{-46}{10}
=-4+3/5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+43}{2*5}=\frac{40}{10}
=4
$